Finding Average Rate of Reaction from measurable quantities
- During a chemical reaction, two things happen
- The quantities of reactants reduce.
- The quantities of products increase.
- Therefore, the rate of the reaction can be determined by
- measuring the decrease of the amount of the reactants over time.
- measuring the increase in the amount of products over time.
- However, the quantity (or change) of the reactants/product may be measurable or immeasurable.
- The easily measured quantity changes include
- Mass
- Concentration (Conductivity)
- Volume of gas
Example
The reaction between calcium carbonate and hydrochloric acid.
CaCO3 + 2HCl → CaCl2 + CO2 + H2O
The rate of the reaction can be determined by
- Measuring the reduces of the mass of the calcium carbonate (reactants) over time
\[\begin{gathered}
{\text{Rate or Reaction }} \hfill \\
{\text{ = }}\frac{{{\text{Mass of CaC}}{{\text{O}}_3}}}{{{\text{Time Taken for Reaction}}}} \hfill \\
\end{gathered} \] - Measuring the increases of the volume of the carbon dioxide gas produced over time.
\[\begin{gathered}
{\text{Rate or Reaction }} \hfill \\
{\text{ = }}\frac{{{\text{Volume of C}}{{\text{O}}_2}{\text{ Produced}}}}{{{\text{Time Taken for Reaction}}}} \hfill \\
\end{gathered} \]
Example:
In a reaction, 5 g of calcium carbonate takes 250 seconds to completely react with the solution of hydrochloric acid. Calculate the average rate for this reaction in units
(a) g s-1 and
(b) mol s-1
[ Relative atomic mass: C 12; O, 16; Ca, 40]
Answer:
a.
Rate of Reaction
= 5g/250s
=0.02gs-1
b. Relative Formula Mass of calcium carbonate (CaCO 3 )
=40+12+3(16) = 100
Number of mole of CaCO3
= 5g/100gmol-1
=0.05 mol
Rate of Reaction
= 0.05mol/250s
=0.0002mols-1
We shall discuss the immeasurable quantity (or changes) in next section.