Certainly! Here are the modified questions with the updated answer formatting:
a. Factorise \(a^2 + 4a\)
\(a(a + 4)\)
b. Factorise \(3x + 4x^2\)
\(x(4x + 3)\)
c. Factorise \(4x^2 – x\)
\(x(4x – 1)\)
d. Factorise \(7x – 3x^2\)
\(x(7 – 3x)\)
e. Factorise \(2x^2 + 4x\)
\(2x(x + 2)\)
f. Factorise \(6x – 3x^2\)
\(-3x(x – 2)\)
g. Factorise \(12x + 16x^3\)
\(4x(3 + 4x^2)\)
h. Factorise \(25x^2 – 15x^3\)
\(5x^2(5 – 3x)\)
i. Factorise \(30x^3 + 10x^2\)
\(10x^2(3x + 1)\)
j. Factorise \(80y^3 – 30y^2\)
\(10y^2(8y – 3)\)
k. Factorise \(12x + 15x^2 – 18x^3\)
\(-3x(6x^2 – 5x – 4)\)
l. Factorise \(4a^3 – 6a + 8a^2\)
No further factorization possible.