Molarity and Number of Moles

Number of mole of solute in a solution can be calculated by using the following formula
$n = \frac{{MV}}{{1000}}$
n = number of mole of solute
M = molaruty of the solution
V = volume of the solution in cm3

Example:
How many moles of zinc sulphate is present in 200cm³ of 0.1 mol dm^-3 zinc sulphate solution?

Answer:
Molarity, M = 0.1 mol dm^-3
Voloume, V = 200cm³
$\begin{gathered} n = \frac{{MV}}{{1000}} \hfill \\ n = \frac{{(0.1)(200)}}{{1000}} \hfill \\ n = 0.02mol \hfill \\ \end{gathered}$

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